Y=-5x^2-10x+15

Solution for Y=-5x^2-10x+15 equation:

=-5Y^2-10Y+15

We move all terms to the left:

-(-5Y^2-10Y+15)=0

We get rid of parentheses

5Y^2+10Y-15=0

a = 5; b = 10; c = -15;
Δ = b2-4ac
Δ = 102-4·5·(-15)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-20}{2*5}=\frac{-30}{10}
=-3
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+20}{2*5}=\frac{10}{10}
=1
$